What is the integral of t^2*cos(t) ?

The integral of t^2*cos(t) is t^2sin(t)-2(-tcos(t)+sin(t))+C

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integral of t^2*cos(t)

\int t^{2} \cdot cos (t) d t

t^{2} sin (t) - 2 (- t cos (t) + sin (t)) + C

Solution steps

\int t^{2} cos (t) d t

Apply Integration By Parts

: t^{2} sin (t) - \int 2 t sin (t) d t

= t^{2} sin (t) - \int 2 t sin (t) d t

\int 2 t sin (t) d t = 2 (- t cos (t) + sin (t))

= t^{2} sin (t) - 2 (- t cos (t) + sin (t))

Add a constant to the solution

= t^{2} sin (t) - 2 (- t cos (t) + sin (t)) + C

\frac{d}{d x} (x^{3} (x - 7)^{2})

y = x^{2} - 4 x + 3, y = 3 + 4 x - x^{2}

x \to - \infty lim (e^{x})

cos (\frac{π x}{4})

\frac{d}{d x} (ln ((x - 1)^{2}))

What is the integral of t^2*cos(t) ?
The integral of t^2*cos(t) is t^2sin(t)-2(-tcos(t)+sin(t))+C