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Popular >

xy^'+4y=5x

Solution

x y^{^{'}} + 4 y = 5 x

Solution

y = x + \frac{c _{1}}{x ^{4}}

Solution steps

x y^{'} (x) + 4 y = 5 x

Solve linear ODE:

y = x + \frac{c _{1}}{x ^{4}}

y = x + \frac{c _{1}}{x ^{4}}

Popular Examples

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x \to \infty lim (2^{x} + 1)

limit as x approaches-2 of f(x)

x \to - 2 lim (f (x))

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\int_{- 3}^{3} x^{2} - 9 d x

(xsec(y/x)+y)dx-xdy=0

(x sec (\frac{y}{x}) + y) d x - x d y = 0

Frequently Asked Questions (FAQ)

What is the solution for xy^'+4y=5x ?
The solution for xy^'+4y=5x is y=x+(c_{1})/(x^4)