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受欢迎的函数 >

critical f(x)=x(x^2-4)^2(x^2-1)

解答

临界点

f (x) = x (x^{2} - 4)^{2} (x^{2} - 1)

解答

x = - 2, x = - \frac{17 + 177}{14}, x = - \frac{17 - 177}{14}, x = \frac{17 - 177}{14}, x = \frac{17 + 177}{14}, x = 2

求解步骤

x (x^{2} - 4)^{2} (x^{2} - 1)

找到

f^{'} (x)

等于零或无定义的点

x = - 2, x = - \frac{17 + 177}{14}, x = - \frac{17 - 177}{14}, x = \frac{17 - 177}{14}, x = \frac{17 + 177}{14}, x = 2

确定不在

f (x)

定义域内的临界点

x (x^{2} - 4)^{2} (x^{2} - 1)

的定义域

: - \infty < x < \infty

所有临界点均在定义域内

x = - 2, x = - \frac{17 + 177}{14}, x = - \frac{17 - 177}{14}, x = \frac{17 - 177}{14}, x = \frac{17 + 177}{14}, x = 2

作图

流行的例子

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