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Beliebt Geometry >

center x^2-14x+y^2+8y+40=0

Lösung

center

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

Lösung

(7, - 4)

Schritte zur Lösung

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

Rewrite

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (7, - 4), r = 5

And the center is:

(7, - 4)

Graph

Beliebte Beispiele

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