What is 2x^2+8x-6y+29=0 ?

The solution to 2x^2+8x-6y+29=0 is Parabola with (h,k)=(-2, 7/2),p= 3/4

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2x^2+8x-6y+29=0

2 x^{2} + 8 x - 6 y + 29 = 0

(h, k) = (- 2, \frac{7}{2}), p = \frac{3}{4}

Solution steps

2 x^{2} + 8 x - 6 y + 29 = 0

Rewrite

2 x^{2} + 8 x - 6 y + 29 = 0

in the standard form

4 \cdot \frac{3}{4} (y - \frac{7}{2}) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{7}{2}), p = \frac{3}{4}

\frac{p ( x )}{x + 6} = 5 x + 3

15 x^{2} = - 42 y

3 x^{2} + 2 y - 3 = 0

x = - \frac{1}{2} (y + 4)^{2} - 5

x^{2} + 4 x + 4 y + 20 = 0

What is 2x^2+8x-6y+29=0 ?
The solution to 2x^2+8x-6y+29=0 is Parabola with (h,k)=(-2, 7/2),p= 3/4