What is 8r^2+22t+15=0 ?

The solution to 8r^2+22t+15=0 is Parabola with (h,k)=(0,-15/22),p=-11/16

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8r^2+22t+15=0

8 r^{2} + 22 t + 15 = 0

(h, k) = (0, - \frac{15}{22}), p = - \frac{11}{16}

Solution steps

8 r^{2} + 22 t + 15 = 0

Rewrite

8 r^{2} + 22 t + 15 = 0

in the standard form:

4 (- \frac{11}{16}) (t - (- \frac{15}{22})) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{15}{22}), p = - \frac{11}{16}

(x - 15)^{2} = - 2 (y - 6)

y^{2} - 7 x - 8 y - 5 = 0

y^{2} - 6 y + 4 x + 5 = 0

y = \frac{1}{4} (x + 4)^{2}

(x - 2)^{2} + y = 0

What is 8r^2+22t+15=0 ?
The solution to 8r^2+22t+15=0 is Parabola with (h,k)=(0,-15/22),p=-11/16