What is 3y^2+4x+4y-14=0 ?

The solution to 3y^2+4x+4y-14=0 is Parabola with (h,k)=(23/6 ,-2/3),p=-1/3

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3y^2+4x+4y-14=0

3 y^{2} + 4 x + 4 y - 14 = 0

(h, k) = (\frac{23}{6}, - \frac{2}{3}), p = - \frac{1}{3}

Solution steps

3 y^{2} + 4 x + 4 y - 14 = 0

Rewrite

3 y^{2} + 4 x + 4 y - 14 = 0

in the standard form

4 (- \frac{1}{3}) (x - \frac{23}{6}) = (y - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{23}{6}, - \frac{2}{3}), p = - \frac{1}{3}

y 2 y = 4 x + 10

x^{2} + 28 = - 6 y - 8 x

x - 9 = y^{2}

y^{2} - 5 y - 7 x - 3 = 0

p (x) \frac{( x )}{x ^{2}} - 4 x + 4 = 0

What is 3y^2+4x+4y-14=0 ?
The solution to 3y^2+4x+4y-14=0 is Parabola with (h,k)=(23/6 ,-2/3),p=-1/3