What is y^2-5y-7x-3=0 ?

The solution to y^2-5y-7x-3=0 is Parabola with (h,k)=(-37/28 , 5/2),p= 7/4

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y^2-5y-7x-3=0

y^{2} - 5 y - 7 x - 3 = 0

(h, k) = (- \frac{37}{28}, \frac{5}{2}), p = \frac{7}{4}

Solution steps

y^{2} - 5 y - 7 x - 3 = 0

Rewrite

y^{2} - 5 y - 7 x - 3 = 0

in the standard form

4 \cdot \frac{7}{4} (x - (- \frac{37}{28})) = (y - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{37}{28}, \frac{5}{2}), p = \frac{7}{4}

p (x) \frac{( x )}{x ^{2}} - 4 x + 4 = 0

y^{2} - 8 x - 6 y + 17 = 0

(x - 4)^{2} = 12 (y - 5)

x + 7 = \frac{1}{36} (y + 3)^{2}

8 (y - 1) = - (x + 3)^{2}

What is y^2-5y-7x-3=0 ?
The solution to y^2-5y-7x-3=0 is Parabola with (h,k)=(-37/28 , 5/2),p= 7/4