What is -x^2+7x+y+30<0 ?

The solution to -x^2+7x+y+30<0 is Parabola with (h,k)=(7/2 ,-169/4),p= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2+7x+y+30<0

- x^{2} + 7 x + y + 30 < 0

(h, k) = (\frac{7}{2}, - \frac{169}{4}), p = \frac{1}{4}

Solution steps

- x^{2} + 7 x + y + 30 < 0

Rewrite

- x^{2} + 7 x + y + 30 < 0

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{169}{4})) = (x - \frac{7}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{7}{2}, - \frac{169}{4}), p = \frac{1}{4}

y^{2} = \frac{3}{2} x

x^{2} = 8 p (x)

3 x^{2} + 80 = - 24 x - 16 y

y^{(2)} + 8 x + 2 y + 33 = 0

x^{2} - 4 x - 12 y - 8 = 0

What is -x^2+7x+y+30<0 ?
The solution to -x^2+7x+y+30<0 is Parabola with (h,k)=(7/2 ,-169/4),p= 1/4