What is (y-3)^2=-1/2 (x+3) ?

The solution to (y-3)^2=-1/2 (x+3) is Parabola with (h,k)=(-3,3),p=-1/8

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(y-3)^2=-1/2 (x+3)

(y - 3)^{2} = - \frac{1}{2} (x + 3)

(h, k) = (- 3, 3), p = - \frac{1}{8}

Solution steps

(y - 3)^{2} = - \frac{1}{2} (x + 3)

Rewrite

(y - 3)^{2} = - \frac{1}{2} (x + 3)

in the standard form:

4 (- \frac{1}{8}) (x - (- 3)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 3, 3), p = - \frac{1}{8}

x = 3 y^{2} - 6 y + 5

Y - X^{2} = 2

0 = - 39 - 3 y - 4 x^{2} + 32 x

(3 x - 6) (x + 1) < o

yy = x + 45

What is (y-3)^2=-1/2 (x+3) ?
The solution to (y-3)^2=-1/2 (x+3) is Parabola with (h,k)=(-3,3),p=-1/8