What is (X+10)^2=3(y-12) ?

The solution to (X+10)^2=3(y-12) is Parabola with (h,k)=(-10,12),p= 3/4

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(X+10)^2=3(y-12)

(X + 10)^{2} = 3 (y - 12)

(h, k) = (- 10, 12), p = \frac{3}{4}

Solution steps

(X + 10)^{2} = 3 (y - 12)

Rewrite

(X + 10)^{2} = 3 (y - 12)

in the standard form:

4 \cdot \frac{3}{4} (y - 12) = (X - (- 10))^{2}

Therefore parabola properties are:

(h, k) = (- 10, 12), p = \frac{3}{4}

x - y^{2} = - 3

x^{2} = \frac{6 r ( x )}{3} - \frac{1}{2}

x^{2} + 3 x - \frac{y}{2} = 7

x^{2} + 6 x - 3 y + 4 = 0

- y = x^{2} - 1

What is (X+10)^2=3(y-12) ?
The solution to (X+10)^2=3(y-12) is Parabola with (h,k)=(-10,12),p= 3/4