What is (y+2)=-3(x+1)^2 ?

The solution to (y+2)=-3(x+1)^2 is Parabola with (h,k)=(-1,-2),p=-1/12

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(y+2)=-3(x+1)^2

(y + 2) = - 3 (x + 1)^{2}

(h, k) = (- 1, - 2), p = - \frac{1}{12}

Solution steps

(y + 2) = - 3 (x + 1)^{2}

Rewrite

(y + 2) = - 3 (x + 1)^{2}

in the standard form:

4 (- \frac{1}{12}) (y - (- 2)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 2), p = - \frac{1}{12}

(y)^{2} = - 2 (x - \frac{5}{2})

x^{2} + 8 x - 24 y + 64 = 0

12 x^{2} + 3 x - 10 y - 1 = 0

y^{2} - 6 y - 8 x - 7 = 0

x^{2} + 2 x - 20 y + 41 = 0

What is (y+2)=-3(x+1)^2 ?
The solution to (y+2)=-3(x+1)^2 is Parabola with (h,k)=(-1,-2),p=-1/12