What is y^2+4x-20-2y=-x ?

The solution to y^2+4x-20-2y=-x is Parabola with (h,k)=(21/5 ,1),p=-5/4

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y^2+4x-20-2y=-x

y^{2} + 4 x - 20 - 2 y = - x

(h, k) = (\frac{21}{5}, 1), p = - \frac{5}{4}

Solution steps

y^{2} + 4 x - 20 - 2 y = - x

Rewrite

y^{2} + 4 x - 20 - 2 y = - x

in the standard form

4 (- \frac{5}{4}) (x - \frac{21}{5}) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (\frac{21}{5}, 1), p = - \frac{5}{4}

f^{2} + 5 g = 3 m d

(x - 5)^{2} = 8 (y + 2)

c = 6000 + 3 q^{2} - 9 q

f (x) (x)^{- 1} = 2 x + 1

y^{2} = 3 x - 5

What is y^2+4x-20-2y=-x ?
The solution to y^2+4x-20-2y=-x is Parabola with (h,k)=(21/5 ,1),p=-5/4