What is f(x)-5=x^2-3x+2 ?

The solution to f(x)-5=x^2-3x+2 is Parabola with (h,k)=(3/2 , 19/4),p= 1/4

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f(x)-5=x^2-3x+2

f (x) - 5 = x^{2} - 3 x + 2

(h, k) = (\frac{3}{2}, \frac{19}{4}), p = \frac{1}{4}

Solution steps

y - 5 = x^{2} - 3 x + 2

Rewrite

y - 5 = x^{2} - 3 x + 2

in the standard form

4 \cdot \frac{1}{4} (y - \frac{19}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{19}{4}), p = \frac{1}{4}

x^{2} - 8 x + 4 y + 20 = 0

(x + 3)^{2} = 24 (y - 2)

y^{2} = \frac{4}{3} x

5 x^{2} - 4 x + P (x) = 0

x = 2 y^{2} + 2 y + 2

What is f(x)-5=x^2-3x+2 ?
The solution to f(x)-5=x^2-3x+2 is Parabola with (h,k)=(3/2 , 19/4),p= 1/4