What is 2x^2+12x+14-14y=0 ?

The solution to 2x^2+12x+14-14y=0 is Parabola with (h,k)=(-3,-2/7),p= 7/4

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2x^2+12x+14-14y=0

2 x^{2} + 12 x + 14 - 14 y = 0

(h, k) = (- 3, - \frac{2}{7}), p = \frac{7}{4}

Solution steps

2 x^{2} + 12 x + 14 - 14 y = 0

Rewrite

2 x^{2} + 12 x + 14 - 14 y = 0

in the standard form

4 \cdot \frac{7}{4} (y - (- \frac{2}{7})) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - \frac{2}{7}), p = \frac{7}{4}

(x - 4)^{2} = - 6 (y + 8)

x^{2} + 5 x + 6 = 0.5 u (y)

x = \frac{1}{9} y^{2}

a^{2} + 5 a - \frac{95}{15} = b

\frac{( y - 2 ) ^{2}}{3} = 8 - x

What is 2x^2+12x+14-14y=0 ?
The solution to 2x^2+12x+14-14y=0 is Parabola with (h,k)=(-3,-2/7),p= 7/4