What is 2k(x)=x^2+3x-9 ?

The solution to 2k(x)=x^2+3x-9 is Parabola with (h,k)=(-3/2 ,-45/8),p= 1/2

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2k(x)=x^2+3x-9

2 k (x) = x^{2} + 3 x - 9

(h, k) = (- \frac{3}{2}, - \frac{45}{8}), p = \frac{1}{2}

Solution steps

2 y = x^{2} + 3 x - 9

Rewrite

2 y = x^{2} + 3 x - 9

in the standard form

4 \cdot \frac{1}{2} (y - (- \frac{45}{8})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{45}{8}), p = \frac{1}{2}

X^{2} - 4 X + Y - 4 Y - 8 = 0

(y + 1)^{2} = 3 (x + 5)

(y)^{2} - 12 x - 10 (y) + 13 = 0

4 x^{2} + 16 y + 40 x + 64 y + 100 = 0

x^{2} + 8 x + 3 - k (x) = 0

What is 2k(x)=x^2+3x-9 ?
The solution to 2k(x)=x^2+3x-9 is Parabola with (h,k)=(-3/2 ,-45/8),p= 1/2