What is 6-3y-4x^2=7x+3 ?

The solution to 6-3y-4x^2=7x+3 is Parabola with (h,k)=(-7/8 , 97/48),p=-3/16

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6-3y-4x^2=7x+3

6 - 3 y - 4 x^{2} = 7 x + 3

(h, k) = (- \frac{7}{8}, \frac{97}{48}), p = - \frac{3}{16}

Solution steps

6 - 3 y - 4 x^{2} = 7 x + 3

Rewrite

6 - 3 y - 4 x^{2} = 7 x + 3

in the standard form

4 (- \frac{3}{16}) (y - \frac{97}{48}) = (x - (- \frac{7}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{8}, \frac{97}{48}), p = - \frac{3}{16}

f (x) - 4 = x^{(2)} - 2 x + 5

(x + 7)^{2} = x^{2} + (y - 5)^{2}

2 \cdot \frac{x}{x - 3} + 2 (x - 3) = 28

y^{2} + 4 x - 9 = 0

\frac{( x - 5 )}{3} = \frac{3 x - 1}{5} + 2 E (x, y) y

What is 6-3y-4x^2=7x+3 ?
The solution to 6-3y-4x^2=7x+3 is Parabola with (h,k)=(-7/8 , 97/48),p=-3/16