What is (y+2)^2=(x+1/4) ?

The solution to (y+2)^2=(x+1/4) is Parabola with (h,k)=(-1/4 ,-2),p= 1/4

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(y+2)^2=(x+1/4)

(y + 2)^{2} = (x + \frac{1}{4})

(h, k) = (- \frac{1}{4}, - 2), p = \frac{1}{4}

Solution steps

(y + 2)^{2} = (x + \frac{1}{4})

Rewrite

(y + 2)^{2} = (x + \frac{1}{4})

in the standard form:

4 \cdot \frac{1}{4} (x - (- \frac{1}{4})) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, - 2), p = \frac{1}{4}

4 x^{2} - 8 x - y + 4 = 0

- 25 x^{2} + y 9^{2} = 225

y^{1} = (x + 1)^{2}

(x + 3) 2 + (y + 1)^{2} = 36

x = 4 y^{2} - 4

What is (y+2)^2=(x+1/4) ?
The solution to (y+2)^2=(x+1/4) is Parabola with (h,k)=(-1/4 ,-2),p= 1/4