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Beliebt Geometry >

leitkurve x^2+16y=0

Lösung

leitkurve

x^{2} + 16 y = 0

Lösung

y = 4

Schritte zur Lösung

Rewrite

x^{2} + 16 y = 0

in the standard form:

4 (- 4) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - 4

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- 4)

Fasse zusammen

y = 4

Graph

Beliebte Beispiele

leitkurve y=4x^2-24x-30

d i rec t r i x y = 4 x^{2} - 24 x - 30

leitkurve 8y=x^2

d i rec t r i x 8 y = x^{2}

leitkurve x^2=36y

d i rec t r i x x^{2} = 36 y

leitkurve (x+4)^2-1

d i rec t r i x (x + 4)^{2} - 1

leitkurve y^2+4x-8y+12=0

d i rec t r i x y^{2} + 4 x - 8 y + 12 = 0