What is the general solution for 16cos(θ)=4 ?

The general solution for 16cos(θ)=4 is θ=1.31811…+2pin,θ=2pi-1.31811…+2pin

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16cos(θ)=4

16 cos (θ) = 4

θ = 1.31811 \dots + 2 πn, θ = 2 π - 1.31811 \dots + 2 πn

Degrees

θ = 75.52248 \dots^{\circ} + 36 0^{\circ} n, θ = 284.47751 \dots^{\circ} + 36 0^{\circ} n

Solution steps

16 cos (θ) = 4

Divide both sides by

16

16 cos (θ) = 4

Divide both sides by

16

\frac{16 cos ( θ )}{16} = \frac{4}{16}

Simplify

cos (θ) = \frac{1}{4}

cos (θ) = \frac{1}{4}

Apply trig inverse properties

cos (θ) = \frac{1}{4}

General solutions for

cos (θ) = \frac{1}{4}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{1}{4}) + 2 πn, θ = 2 π - arccos (\frac{1}{4}) + 2 πn

θ = arccos (\frac{1}{4}) + 2 πn, θ = 2 π - arccos (\frac{1}{4}) + 2 πn

Show solutions in decimal form

θ = 1.31811 \dots + 2 πn, θ = 2 π - 1.31811 \dots + 2 πn

- 5 π sin (π x) = 0

u, x = sin (u)

\frac{cos ( x )}{1 - cos ^{2} ( x )} = 23

- 3 sin (2 x) = 5 cos (2 x)

3 cot (x) - 1 = 0, 0 \leq x \leq 2 π

What is the general solution for 16cos(θ)=4 ?
The general solution for 16cos(θ)=4 is θ=1.31811…+2pin,θ=2pi-1.31811…+2pin