Is sin(-(2pi)/5)=-sin((2pi)/5) ?

The answer to whether sin(-(2pi)/5)=-sin((2pi)/5) is True

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prove sin(-(2pi)/5)=-sin((2pi)/5)

prove

sin (- \frac{2 π}{5}) = - sin (\frac{2 π}{5})

True

Solution steps

sin (- \frac{2 π}{5}) = - sin (\frac{2 π}{5})

Manipulating left side

sin (- \frac{2 π}{5})

Use the negative angle identity:

sin (- x) = - sin (x)

= - sin (\frac{2 π}{5})

We showed that the two sides could take the same form

\Rightarrow True

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

sin^{2} (u) = \frac{( 1 - cos ( 2 u ) )}{2}

tan (θ) - sec (θ) = - \frac{cos ( θ )}{1 + sin ( θ )}

2 cos^{2} (x) - 1 = - 2 sin^{2} (x) + 1

sin (x) = - 1 = sin (0) = - 1

Is sin(-(2pi)/5)=-sin((2pi)/5) ?
The answer to whether sin(-(2pi)/5)=-sin((2pi)/5) is True