Is cos(x^2)= 1/(sec(x^2)) ?

The answer to whether cos(x^2)= 1/(sec(x^2)) is True

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prove cos(x^2)= 1/(sec(x^2))

prove

cos (x^{2}) = \frac{1}{sec ( x ^{2} )}

True

Solution steps

cos (x^{2}) = \frac{1}{sec ( x ^{2} )}

Use the basic trigonometric identity:

cos (x) = \frac{1}{sec ( x )}

\Rightarrow True

\frac{cos ( 2 b ) - 1}{sin ( 2 b )} = \frac{- tan ( b )}{1}

sin (x) = cos (x - π)

cot (x) + tan (x) = \frac{2}{sin ( 2 x )}

\frac{1}{2} (1 + cos (2 x)) = cos^{2} (x)

sec (\frac{5 π}{6}) = \frac{- 2}{3}

Is cos(x^2)= 1/(sec(x^2)) ?
The answer to whether cos(x^2)= 1/(sec(x^2)) is True