What is the general solution for tan(α)=-1 ?

The general solution for tan(α)=-1 is α=(3pi)/4+pin

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tan(α)=-1

tan (α) = - 1

α = \frac{3 π}{4} + πn

Degrees

α = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (α) = - 1

General solutions for

tan (α) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

α = \frac{3 π}{4} + πn

α = \frac{3 π}{4} + πn

sin (3 π x) = 1

cos (z) = - 2

tan (θ) = \frac{5}{6.7}

2 cos (t) = - 2

sec^{2} (x) + 3 = 1

What is the general solution for tan(α)=-1 ?
The general solution for tan(α)=-1 is α=(3pi)/4+pin