8=4^{x+1}

Lösung

8 = 4^{x + 1}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

8 = 4^{x + 1}

Wende Exponentenregel an

3 = 2 (x + 1)

Löse

3 = 2 (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

8 = 4^{x + 2}

0 = (\frac{1}{2})^{x} - 4

0 = (\frac{1}{2})^{x} - 3

4^{x^{2}} = 1 6^{5 x - 8}

1 6^{x} - 5 (2^{2 x - 1}) + 1 = 0