(3-2i)(x+i)=17+iy

解答

(3 - 2 i) (x + i) = 17 + i y

x = 5, y = - 7

求解步骤

(3 - 2 i) (x + i) = 17 + i y

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(3 - 2 i) (x + i) : (3 x + 2) + i (3 - 2 x)

(3 x + 2) + i (3 - 2 x) = 17 + i y

复数仅在实部和虚部均相等时才相等改写为方程组:

[3 x + 2 = 17 3 - 2 x = y]

[3 x + 2 = 17 3 - 2 x = y] : x = 5, y = - 7

x = 5, y = - 7

z^{2} + z \cdot i + 2 = 0

(a + 4 i) + (7 + bi) = 5 + 7 i

\frac{( 1 + ai )}{5 + bi} = 1 + 5 i

p = v \cdot i

(1 + 3)^{11} = a + ib