a+3+2bi=5-4i

解答

a + 3 + 2 bi = 5 - 4 i

a = 2, b = - 2

求解步骤

a + 3 + 2 bi = 5 - 4 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[a + 3 = 5 2 b = - 4]

[a + 3 = 5 2 b = - 4] : a = 2, b = - 2

a = 2, b = - 2

0 = 1 0^{5} (10 + i x) (1000 + i x)

- x^{2} = 2 i

x^{2} = 1184 + 125.6637 i

2 w^{2} + (- 6 + 7 i) w - 11 + 2 i = 0

x^{2} + (2 - 2 i) x - (4 + 2 i) = 0