e^{x+1}=4^{x+4}

Lösung

e^{x + 1} = 4^{x + 4}

x = \frac{8 ln ( 2 ) - 1}{1 - 2 ln ( 2 )}

Dezimale

x = - 11.76609 \dots

Schritte zur Lösung

e^{x + 1} = 4^{x + 4}

Wende Exponentenregel an

x + 1 = (x + 4) ln (4)

Löse

x + 1 = (x + 4) ln (4) : x = \frac{8 ln ( 2 ) - 1}{1 - 2 ln ( 2 )}

x = \frac{8 ln ( 2 ) - 1}{1 - 2 ln ( 2 )}

5 (2)^{x + 1} = 9

7 e^{9 x} = 20

9^{3 x} = 2 7^{x - 2}

\frac{2 ^{4 x - 1}}{2 ^{3 x + 2}} = 16

3^{x - 1} - 3^{x} + 3^{x + 1} = 63