What are the solutions to the equation 3z^2+10z-25=0 ?

The solutions to the equation 3z^2+10z-25=0 are z= 5/3 ,z=-5

Find the zeros of 3z^2+10z-25=0

The zeros of 3z^2+10z-25=0 are z= 5/3 ,z=-5

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3 z^{2} + 10 z - 25 = 0

z = \frac{5}{3}, z = - 5

Solution steps

3 z^{2} + 10 z - 25 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 25 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 25) = 20

z_{1, 2} = \frac{- 10 \pm 20}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 10 + 20}{2 \cdot 3}, z_{2} = \frac{- 10 - 20}{2 \cdot 3}

z = \frac{- 10 + 20}{2 \cdot 3} : \frac{5}{3}

z = \frac{- 10 - 20}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

z = \frac{5}{3}, z = - 5

- 3 < \frac{1}{x} \leq 1

x^{2} = 39

(1 - 2 x)^{2} = 0

- 3 z \geq 15

5 x^{2} = 16 + 7 x

What are the solutions to the equation 3z^2+10z-25=0 ?
The solutions to the equation 3z^2+10z-25=0 are z= 5/3 ,z=-5
Find the zeros of 3z^2+10z-25=0
The zeros of 3z^2+10z-25=0 are z= 5/3 ,z=-5