What are the solutions to the equation (1-2x)^2=0 ?

The solutions to the equation (1-2x)^2=0 are x= 1/2

Find the zeros of (1-2x)^2=0

The zeros of (1-2x)^2=0 are x= 1/2

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(1 - 2 x)^{2} = 0

x = \frac{1}{2}

Solution steps

(1 - 2 x)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

1 - 2 x = 0 : x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

- 3 z \geq 15

5 x^{2} = 16 + 7 x

6^{2} + 5^{2}

28 x^{3} y^{3}

\frac{2 x + 1}{7} > \frac{x - 3}{4}

What are the solutions to the equation (1-2x)^2=0 ?
The solutions to the equation (1-2x)^2=0 are x= 1/2
Find the zeros of (1-2x)^2=0
The zeros of (1-2x)^2=0 are x= 1/2