What is the solution for (dy}{dx}=\frac{e^{3x}+3xy+y)/x ?

The solution for (dy}{dx}=\frac{e^{3x}+3xy+y)/x is y=-e^{3x}+(c_{1}x)/(e^{-3x+c_{1)}}

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(dy}{dx}=\frac{e^{3x}+3xy+y)/x

\frac{d y}{d x} = \frac{e ^{3 x} + 3 x y + y}{x}

y = - e^{3 x} + \frac{c _{1} x}{e ^{- 3 x + c_{1}}}

Solution steps

\frac{d y}{d x} = \frac{e ^{3 x} + 3 x y + y}{x}

Solve linear ODE:

y = - e^{3 x} + \frac{c _{1} x}{e ^{- 3 x + c_{1}}}

y = - e^{3 x} + \frac{c _{1} x}{e ^{- 3 x + c_{1}}}

\frac{d ^{2}}{d x ^{2}} (\frac{3 x - 2}{2 x + 1})

\frac{d}{d x} (\frac{lo g _{3} ( x )}{lo g _{7} ( x )})

\int x^{2} - cos (x) d x

d x + e^{5 x} d y = 0

s^{2} + 2 s + 1

What is the solution for (dy}{dx}=\frac{e^{3x}+3xy+y)/x ?
The solution for (dy}{dx}=\frac{e^{3x}+3xy+y)/x is y=-e^{3x}+(c_{1}x)/(e^{-3x+c_{1)}}