y^{''}+4y^'-32y=0

Lösung

y^{^{''}} + 4 y^{^{'}} - 32 y = 0

y = c_{1} e^{4 t} + c_{2} e^{- 8 t}

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) - 32 y = 0

Solve linear ODE:

y = c_{1} e^{4 t} + c_{2} e^{- 8 t}

y = c_{1} e^{4 t} + c_{2} e^{- 8 t}

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