What is the derivative of x+e^x-1/x ?

The derivative of x+e^x-1/x is 1+e^x+1/(x^2)

What is the first derivative of x+e^x-1/x ?

The first derivative of x+e^x-1/x is 1+e^x+1/(x^2)

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derivative of

x + e^{x} - \frac{1}{x}

1 + e^{x} + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x + e^{x} - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (e^{x}) - \frac{d}{d x} (\frac{1}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 1 + e^{x} - (- \frac{1}{x ^{2}})

Simplify

= 1 + e^{x} + \frac{1}{x ^{2}}

\int \frac{( 4 x - 5 )}{( x - 2 ) ( x + 3 )} d x

\int \frac{y}{x ( x + y )} d x

x y^{^{'}} + y = e^{x}, y (1) = 6

\int \frac{9}{6 + 9 x} d x

\int (2^{x} + e^{π}) d x

What is the derivative of x+e^x-1/x ?
The derivative of x+e^x-1/x is 1+e^x+1/(x^2)
What is the first derivative of x+e^x-1/x ?
The first derivative of x+e^x-1/x is 1+e^x+1/(x^2)