What is (\partial)/(\partial u)(u+2v) ?

The answer to (\partial)/(\partial u)(u+2v) is 1

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(\partial)/(\partial u)(u+2v)

\frac{\partial}{\partial u} (u + 2 v)

1

Solution steps

\frac{\partial}{\partial u} (u + 2 v)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (2 v)

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (2 v) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} (x - 2 π)

y = x^{2} + 2 x - 2

y^{^{'}} = e^{9 y - x}

f (x) = x^{3}, at x = - 5

x \to 0 lim (1 - cos (3 x))

What is (\partial)/(\partial u)(u+2v) ?
The answer to (\partial)/(\partial u)(u+2v) is 1