What is the derivative of-sec(1/x+7x) ?

The derivative of-sec(1/x+7x) is -sec(1/x+7x)tan(1/x+7x)(-1/(x^2)+7)

What is the first derivative of-sec(1/x+7x) ?

The first derivative of-sec(1/x+7x) is -sec(1/x+7x)tan(1/x+7x)(-1/(x^2)+7)

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derivative of

- sec (\frac{1}{x} + 7 x)

- sec (\frac{1}{x} + 7 x) tan (\frac{1}{x} + 7 x) (- \frac{1}{x ^{2}} + 7)

Solution steps

\frac{d}{d x} (- sec (\frac{1}{x} + 7 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sec (\frac{1}{x} + 7 x))

Apply the chain rule:

sec (\frac{1}{x} + 7 x) tan (\frac{1}{x} + 7 x) \frac{d}{d x} (\frac{1}{x} + 7 x)

= sec (\frac{1}{x} + 7 x) tan (\frac{1}{x} + 7 x) \frac{d}{d x} (\frac{1}{x} + 7 x)

\frac{d}{d x} (\frac{1}{x} + 7 x) = - \frac{1}{x ^{2}} + 7

= - sec (\frac{1}{x} + 7 x) tan (\frac{1}{x} + 7 x) (- \frac{1}{x ^{2}} + 7)

\frac{d}{d x} (x e^{- 2 x^{2}})

\frac{\partial}{\partial x} (7 e^{x y})

\frac{d}{d x} (\frac{x}{ln ( x )})

What is the derivative of-sec(1/x+7x) ?
The derivative of-sec(1/x+7x) is -sec(1/x+7x)tan(1/x+7x)(-1/(x^2)+7)
What is the first derivative of-sec(1/x+7x) ?
The first derivative of-sec(1/x+7x) is -sec(1/x+7x)tan(1/x+7x)(-1/(x^2)+7)