taylor e^{1/x}0

Lösung

taylor

e^{\frac{1}{x}} 0

\dots

Schritte zur Lösung

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( e ^{\frac{1}{x}} \cdot 0 ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{\frac{1}{x}} \cdot 0 ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{\frac{1}{x}} \cdot 0 ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} (x - 1) + \frac{0}{2 !} (x - 1)^{2} + \frac{0}{3 !} (x - 1)^{3} + \frac{0}{4 !} (x - 1)^{4} + \frac{0}{5 !} (x - 1)^{5} + \frac{0}{6 !} (x - 1)^{6} + \frac{0}{7 !} (x - 1)^{7} + \frac{0}{8 !} (x - 1)^{8} + \frac{0}{9 !} (x - 1)^{9} + \frac{0}{10 !} (x - 1)^{10} + \dots

Fasse zusammen

= \dots

x \to + 0 lim (\frac{2 ^{x} - 3 ^{x}}{x})

d er i v a t i v e e^{9 e^{x}}

\frac{d y}{d x} = \frac{1}{6 x - 42}

t an g e n t f (x) = tan (x), at x = π

\int \frac{x}{8 + 2 x - x ^{2}} d x