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Popular >

y^'-6y^'+9y=0

Solution

y^{^{'}} - 6 y^{^{'}} + 9 y = 0

Solution

y = e^{\frac{9 t + c _{1}}{5}}

Solution steps

y^{'} (t) - 6 y^{'} (t) + 9 y = 0

Solve separable ODE:

y = e^{\frac{9 t + c _{1}}{5}}

y = e^{\frac{9 t + c _{1}}{5}}

Popular Examples

sum from n=0 to infinity of 3(-1/3)^n

n = 0 \sum \infty 3 (- \frac{1}{3})^{n}

tangent of y=x^3-2x+1,(4,57)tangent of

y = x^{3} - 2 x + 1, (4, 57)

f(x)=(sin(x))/(1+cos(x))

f (x) = \frac{sin ( x )}{1 + cos ( x )}

derivative of (x^2/(a^2)+(y^2)/(b^2)-1)

\frac{d}{d x} (\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} - 1)

y^{^{'}} = \frac{x}{6 y}

Frequently Asked Questions (FAQ)

What is the solution for y^'-6y^'+9y=0 ?
The solution for y^'-6y^'+9y=0 is y=e^{(9t+c_{1})/5}