What is the solution for derivative of y=(3-e^{-x})^2 ?

The solution for derivative of y=(3-e^{-x})^2 is y=9x+6e^{-x}-1/2 e^{-2x}+c_{1}

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derivative of y=(3-e^{-x})^2

\frac{d}{d x} y = (3 - e^{- x})^{2}

y = 9 x + 6 e^{- x} - \frac{1}{2} e^{- 2 x} + c_{1}

Solution steps

\frac{d y}{d x} = (3 - e^{- x})^{2}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (3 - e^{- x})^{2} d x

\int (3 - e^{- x})^{2} d x = 9 x + 6 e^{- x} - \frac{1}{2} e^{- 2 x} + c_{1}

y = 9 x + 6 e^{- x} - \frac{1}{2} e^{- 2 x} + c_{1}

\int \frac{1}{4 x - 10} d x

\frac{\partial}{\partial x} (sin^{2} (θ))

x = - 5, x = 1, y = 2 x^{2} + 4, y = 0

\int_{- 1}^{1} x + 1 d x

x \to 0 + lim (\frac{1}{x})

What is the solution for derivative of y=(3-e^{-x})^2 ?
The solution for derivative of y=(3-e^{-x})^2 is y=9x+6e^{-x}-1/2 e^{-2x}+c_{1}