What is area x=-5,x=1,y=2x^2+4,y=0 ?

The answer to area x=-5,x=1,y=2x^2+4,y=0 is 108

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area x=-5,x=1,y=2x^2+4,y=0

area

x = - 5, x = 1, y = 2 x^{2} + 4, y = 0

108

Solution steps

Apply the area formula:

\int_{- 5}^{1} 2 x^{2} + 4 d x

Solve

\int_{- 5}^{1} 2 x^{2} + 4 d x : 108

The area is:

= 108

\int_{- 1}^{1} x + 1 d x

x \to 0 + lim (\frac{1}{x})

\int_{0}^{\frac{3 π}{2}} cos^{3} (33 x) d x

\int_{0}^{\frac{1}{2}} \frac{1}{1 + 4 x ^{2}} d x

\frac{\partial}{\partial y} (\frac{x ^{2}}{y + 2})

What is area x=-5,x=1,y=2x^2+4,y=0 ?
The answer to area x=-5,x=1,y=2x^2+4,y=0 is 108