What is the derivative of sqrt(x+a) ?

The derivative of sqrt(x+a) is 1/(2sqrt(x+a))

What is the first derivative of sqrt(x+a) ?

The first derivative of sqrt(x+a) is 1/(2sqrt(x+a))

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\frac{d}{d x} (x + a)

\frac{1}{2 x + a}

Solution steps

\frac{d}{d x} (x + a)

Apply the chain rule:

\frac{1}{2 x + a} \frac{d}{d x} (x + a)

= \frac{1}{2 x + a} \frac{d}{d x} (x + a)

\frac{d}{d x} (x + a) = 1

= \frac{1}{2 x + a} \cdot 1

Simplify

= \frac{1}{2 x + a}

\frac{d}{d x} (ln (x - y))

\frac{\partial}{\partial x} (\frac{x \cdot y}{x ^{2} + y ^{2}})

\int x (sin (x) - cos (x^{2})) d x

y^{^{''}} + 4 y = 3 sin (x)

What is the derivative of sqrt(x+a) ?
The derivative of sqrt(x+a) is 1/(2sqrt(x+a))
What is the first derivative of sqrt(x+a) ?
The first derivative of sqrt(x+a) is 1/(2sqrt(x+a))