What is the derivative of 1/(\sqrt[9]{x}) ?

The derivative of 1/(\sqrt[9]{x}) is -1/(9x^{10/9)}

What is the first derivative of 1/(\sqrt[9]{x}) ?

The first derivative of 1/(\sqrt[9]{x}) is -1/(9x^{10/9)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- \frac{1}{9 x ^{\frac{10}{9}}}

Solution steps

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- \frac{1}{9}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{9} x^{- \frac{1}{9} - 1}

Simplify

- \frac{1}{9} x^{- \frac{1}{9} - 1} : - \frac{1}{9 x ^{\frac{10}{9}}}

= - \frac{1}{9 x ^{\frac{10}{9}}}

\frac{\partial}{\partial x} (\frac{x \cdot y}{x ^{2} + y ^{2}})

\int x (sin (x) - cos (x^{2})) d x

y^{^{''}} + 4 y = 3 sin (x)

\frac{d V}{12 - 2 V} = d t, V (0) = 1

\frac{\partial}{\partial x} (\frac{x + 2 y}{3 x + 4 y})

What is the derivative of 1/(\sqrt[9]{x}) ?
The derivative of 1/(\sqrt[9]{x}) is -1/(9x^{10/9)}
What is the first derivative of 1/(\sqrt[9]{x}) ?
The first derivative of 1/(\sqrt[9]{x}) is -1/(9x^{10/9)}