What is the first derivative of 2x+3y ?

The first derivative of 2x+3y is 2

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derivative of 2x+3y

derivative of

2 x + 3 y

2

Solution steps

\frac{d}{d x} (2 x + 3 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (3 y)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 y) = 0

= 2 + 0

Simplify

= 2

\int_{- 2}^{- 1} (x^{2} - x - 2) d x

f (x) = e^{x} ln (x)

x \to 0 lim (\frac{sin ( 4 x )}{6})

\frac{\partial}{\partial y} (x e^{y^{2}} + y ln (x))

\int \frac{6}{( x - 4 ) ( x + 2 )} d x