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Popular >

y^'=e^y5^x

Solution

y^{^{'}} = e^{y} 5^{x}

Solution

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

Solution steps

y^{'} (x) = e^{y} 5^{x}

Solve separable ODE:

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

y = - ln (- \frac{5 ^{x}}{ln ( 5 )} - c_{1})

Popular Examples

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n = 1 \sum \infty \frac{60}{6 ^{n}}

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\int e^{- 0.08 x} d x

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\frac{d}{d x} (tan^{2} (x) cos (x))

sum from n=0 to infinity of 6(3/4)^n

n = 0 \sum \infty 6 (\frac{3}{4})^{n}

integral of (ln(11x))^2

\int (ln (11 x))^{2} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^y5^x ?
The solution for y^'=e^y5^x is y=-ln(-(5^x)/(ln(5))-c_{1})