integral from 1 to 2 of (1-x)

Lösung

\int_{1}^{2} (1 - x) d x

- \frac{1}{2}

Dezimale

- 0.5

Schritte zur Lösung

\int_{1}^{2} 1 - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d x - \int_{1}^{2} x d x

\int_{1}^{2} 1 d x = 1

\int_{1}^{2} x d x = \frac{3}{2}

= 1 - \frac{3}{2}

Vereinfache

1 - \frac{3}{2} : - \frac{1}{2}

= - \frac{1}{2}

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