What is the derivative of-8e^{-8x} ?

The derivative of-8e^{-8x} is 64e^{-8x}

What is the first derivative of-8e^{-8x} ?

The first derivative of-8e^{-8x} is 64e^{-8x}

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\frac{d}{d x} (- 8 e^{- 8 x})

64 e^{- 8 x}

Solution steps

\frac{d}{d x} (- 8 e^{- 8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (e^{- 8 x})

Apply the chain rule:

e^{- 8 x} \frac{d}{d x} (- 8 x)

= e^{- 8 x} \frac{d}{d x} (- 8 x)

\frac{d}{d x} (- 8 x) = - 8

= - 8 e^{- 8 x} (- 8)

Simplify

= 64 e^{- 8 x}

\frac{\partial}{\partial r} (r^{2} + s^{2})

x \to 3 - lim (\frac{5 x}{x ^{2} - 9})

\int_{0}^{5} \frac{1}{25 - x ^{2}} d x

x \to - 1 - lim (\frac{9}{x ^{3} - 1})

\int \frac{3}{16 - x ^{2}} d x

What is the derivative of-8e^{-8x} ?
The derivative of-8e^{-8x} is 64e^{-8x}
What is the first derivative of-8e^{-8x} ?
The first derivative of-8e^{-8x} is 64e^{-8x}