4x^{''}+15x^'+14x=0

Lösung

4 x^{^{''}} + 15 x^{^{'}} + 14 x = 0

x = c_{1} e^{- \frac{7 t}{4}} + c_{2} e^{- 2 t}

Schritte zur Lösung

4 x^{''} (t) + 15 x^{'} (t) + 14 x = 0

Solve linear ODE:

x = c_{1} e^{- \frac{7 t}{4}} + c_{2} e^{- 2 t}

x = c_{1} e^{- \frac{7 t}{4}} + c_{2} e^{- 2 t}

y^{^{''}} + 5 y^{^{'}} - 2 y = 0, y (0) = 5, y^{^{'}} (0) = - 5

3 y^{^{''}} + 4 y^{^{'}} + y = 0, y (0) = 2, y^{^{'}} (0) = - 1

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{'''}} + y^{^{''}} - 6 y^{^{'}} + 4 y = 0

y^{^{''}} + 2 y + y = 0, y (0) = x e^{- x}