y^{''}+0y^'+y=0

Lösung

y^{^{''}} + 0 y^{^{'}} + y = 0

y = c_{1} cos (t) + c_{2} sin (t)

Schritte zur Lösung

y^{''} (t) + 0 y^{'} (t) + y = 0

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t)

y = c_{1} cos (t) + c_{2} sin (t)

c \frac{d ^{2} y}{d x ^{2}} = y

2 x^{^{''}} + 72 x = 0

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 6, y^{^{'}} (0) = 25

y^{^{''}} + 1 y^{^{'}} + y = 0

y^{^{''}} + a y = 0, y (- 1) = 0, y (1) = 0