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Beliebt Rechnen >

y^{''}+1y^'+y=0

Lösung

y^{^{''}} + 1 y^{^{'}} + y = 0

Lösung

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Schritte zur Lösung

y^{''} (t) + 1 y^{'} (t) + y = 0

Solve linear ODE:

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{3 t}{2}) + c_{2} sin (\frac{3 t}{2}))

Graph

Beliebte Beispiele

y^{''}+ay=0,y(-1)=0,y(1)=0

y^{^{''}} + a y = 0, y (- 1) = 0, y (1) = 0

y^{''}-y^'-30y=0,y(0)=x,y^'(0)=5

y^{^{''}} - y^{^{'}} - 30 y = 0, y (0) = x, y^{^{'}} (0) = 5

x^{^{''}} = a x

-3y^{''}+1/12 y=0

- 3 y^{^{''}} + \frac{1}{12} y = 0

1/8 y^{''}+4y^'+28y=0,y(0)=0,y^'(0)=8

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 28 y = 0, y (0) = 0, y^{^{'}} (0) = 8