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Popular >

extreme f(x)=x^2+2

Solution

extreme points

f (x) = x^{2} + 2

Solution

Minimum (0, 2)

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 2 : 2

Minimum (0, 2)

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slope ofintercept 5x+5y=15 slope intercept

5 x + 5 y = 15

extreme f(x)= 5/4 x^2-12x+34 extreme points

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domain of f(x)=(sqrt(x+2))/(x^2-2x-8)domain

f (x) = \frac{x + 2}{x ^{2} - 2 x - 8}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2 ?
The extreme f(x)=x^2+2 is Minimum(0,2)