extreme y=100+1/2 x+(1800)/x

Lösung

extrempunkte

y = 100 + \frac{1}{2} x + \frac{1800}{x}

Maximum (- 60, 40), Minimum (60, 160)

Schritte zur Lösung

f^{'} (x) = - \frac{1800}{x ^{2}} + \frac{1}{2}

Intervalle finden:

Ansteigend

: - \infty < x < - 60,

Absteigend

: - 60 < x < 0,

Absteigend

: 0 < x < 60,

Ansteigend

: 60 < x < \infty

Stecke

x = - 60

100 + \frac{1}{2} x + \frac{1800}{x} : 40

Maximum (- 60, 40)

Stecke

x = 60

100 + \frac{1}{2} x + \frac{1800}{x} : 160

Minimum (60, 160)

Maximum (- 60, 40), Minimum (60, 160)

e x t re m e f (x) = x^{3} - 15 x

e x t re m e f (x) = x^{3} - 3 x, - 1 \leq x \leq 2

\frac{d}{d r} (4 k^{\frac{3}{2}} (\frac{r}{w}))

e x t re m e f (x) = x + 10 1 - x, - 2 \leq x \leq 5

e x t re m e f (x) = 2 x^{3} + x^{2} - 11 x