foki 9x^2+4y^2+32y+28=0

Lösung

foki

9 x^{2} + 4 y^{2} + 32 y + 28 = 0

(0, - 4 + 5), (0, - 4 - 5)

Schritte zur Lösung

(h, k + c), (h, k - c)

Calculate ellipse properties

9 x^{2} + 4 y^{2} + 32 y + 28 = 0 :

Ellipse with center

(h, k) = (0, - 4), b = 3, a = 2

(0, - 4 + c), (0, - 4 - c)

Compute

c :

c = 3^{2} - 2^{2} : 5

(0, - 4 + 5), (0, - 4 - 5)

f oc i \frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1

f oc i 4 x^{2} + 25 y^{2} + 40 x - 150 y + 225 = 0

f oc i \frac{x ^{2}}{\frac{81}{4}} + \frac{y ^{2}}{\frac{25}{16}} = 1

f oc i \frac{( y - 1 ) ^{2}}{4} + \frac{( x ^{2} )}{25} = 1

f oc i x^{2} + 4 y^{2} - 4 x - 8 y - 92 = 0